编程语言语法

程序类型语法	python	C++/C	java
或	or	\	\
与	and	&&
非	not	!
条件语句	if 条件 : 制表符 elseif 或elif: 制表符 else : 制表符	if (条件){ } else if() { } else { }
循环语句	1.for for x in [1,2,3,…] : 制表符 2.while while 循环条件: 制表符	1.for for(int i=0;i\<10;i++){} 2.while while(条件){} do{ }while(条件)
语句之间	制表符	{}
dict表	d = {‘Michael’: 95, ‘Bob’: 75, ‘Tracy’: 85}
set	s1 = set([1, 2, 3]) s2 = set([2, 3, 4]) print(s1 & s2) print(s1 \	s2) s1.add(4) s1.remove(1)
平方	import math math.sqrt(2)
函数定义	def wan_find(list, col, list2): col_max = 0 col_y = 0 col=col # a = np.linspace(0, 5, 5); for i in [0, 1, 2, 3, 4, 5]: if col_max \< list[i, col] and (i not in list2): col_y = i col_max = list[i, col] return col_y, col_max	int wan_find(float list[][], int col,int list2){ }
默认参数	def product(x, y=1, z=1, k=1): return x * y * z * k
递归函数	def fact(n): return fact_iter(n, 1) def fact_iter(num, product): if num == 1: return product return fact_iter(num - 1, num * product)
map	r =map(f, [1, 2, 3, 4, 5, 6, 7, 8, 9]) list(r)
reduce	reduce(f, [x1, x2, x3, x4]) = f(f(f(x1, x2), x3), x4)
filter	def is_odd(n): return n % 2 == 1 r=filter(is_odd, [1, 2, 4, 5, 6, 9, 10, 15]) print(list(r))
快速排序	sorted([36, 5, -12, 9, -21], key=abs) key=abs按照绝对值排序
面向对象	class Student(object): def _init_(self, name, score): self.name = name self.score = score def print_score(self): print(‘%s: %s’ % (self.name, self.score)) def get_grade(self): if self.score >= 90: return ‘A’ elif self.score >= 60: return ‘B’ else: return ‘C’